How do you factor #x^2+4x-12#?

1 Answer
Meave60
May 2, 2015

The answer is #(x-2)(x+6)#

Determine what two numbers when added together make the coefficient of #x#, in this case #4#, and when multiplied together make the constant, in this case #-12#. For this problem, the two numbers are #6# and #-2#.

#6+(-2)=4#, and #6xx(-2)=12#.

The factorization of #x^2+4x-12=(x-2)(x+6)#.

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