How do you factor #x^2-25#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Meave60 May 2, 2015 The answer is #(x+5)(x-5)# . #(x^2-25)# fits the pattern of the difference of squares in which #(a^2-b^2)=(a+b)(a-b)#. The factorization of #(x^2-25)=(x^2-5^2)# = #(x+5)(x-5)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 44429 views around the world You can reuse this answer Creative Commons License