How do you factor #-x^2+15x-50=0#?

1 Answer
May 3, 2015

#-x^2+15x-50 = 0#
or, equivalnetly
#(-1)(x^2-15x+50) = 0#

We are looking for two constants: #a# and #b# such that
#a+b= -15#
and
#axxb = 50#

The obvious pair is #(a,b) = (-5,-10)#
gives us
#-x^2+15x-50 = 0#
#-= (-1)(x-5)(x-10) = 0#

Note that it is unusual to be asked to factor an equation; normally we only factor expressions:
#-x^2+15x-50 = (-1)(x-5)(x-10)#

It may be that the intent was to extract
#x-5 = 0#
and
#x-10=0#
as factors of the original equation (check with your instructor).