How do you factor #49x^2 - 121y^2#?

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Answer 1 · 2015-05-04T07:20:47

#49x^2 - 121y^2# can be written as #(7x)^2 - (11y)^2#

this is of the form:

#a^2 - b^2 = ( a + b) (a -b ) #

here: #a = 7x# and # b = 11y#

so ,

# (7x)^2 - (11y)^2= (7x+11y) (7x- 11y) #

the factorized form of #49x^2 - 121y^2# is:

#(7x+11y) (7x- 11y)#