How do you factor $100 m^{8} - 9$ $100m^8 - 9$ ?

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Answer 1 · 2015-05-06T21:08:43

This fits the form of the difference of squares.

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2-b^2=(a-b)(a+b)$

$100 m^{8} - 9 = {(10 m^{4})}^{2} - 3^{2}$ $100m^8-9=(10m^4)^2-3^2$

$a = 10 m$ $a=10m$
$b = 3$ $b=3$

$100 m^{8} - 9 = (10 m^{4} - 3) (10 m^{4} + 3)$ $100m^8-9=(10m^4-3)(10m^4+3)$

How do you factor 100m8−9100m^8 - 9?