How do you factor #x^4-2x^3-12x^2+18x+27#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Phillip E. May 7, 2015 Answer #(x+1)(x-3)^2(x+3)# Try #x=-1# gives #1+2-12-18+27=0# so #x+1# is a factor. Dividing by #(x+1)# gives #x^3-3x^2-9x+27# Try #x=3# in cubic gives #27-27-27+27=0# so #x-3# is a factor Dividing by #(x-3)# gives #x^2-9# which factors to #(x-3)(x+3)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1687 views around the world You can reuse this answer Creative Commons License