How do you factor #9a^2 + 24a + 16 #? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. May 10, 2015 #9a^2+24a+16 = (3a+4)(3a+4)# I found this by noticing that #9a^2 = (3a)^2# and #16 = 4^2#, then seeing what coefficient of #a# came out when I multiplied #(3a + 4)(3a + 4)#. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2720 views around the world You can reuse this answer Creative Commons License