How do you factor #32x^2 – 8#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Don't Memorise May 13, 2015 #8# is a common factor to both the terms in the expression: #32x^2 - 8 = 8(4x^2 - 1)# # = 8((2x)^2 - 1^2)# We know that #color(blue)(a^2 - b^2 = (a+b)(a-b)# Hence the above expression can be written as : # = color(green)(8(2x+1)(2x-1)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2799 views around the world You can reuse this answer Creative Commons License