How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. #v(t) = t^2 + 11t - 4#?

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Answer 1 · 2015-05-19T01:05:10

#v(t) = t^2 + 11t - 4.#
Coordinates of vertex: (x, y)

#x = (-b/2a) = (-11/2)#

#y = v(-11/2) = 121/4 - 121/2 - 4 = -137/4#

The function in vertex form:

#v(t) = (x + 11/2)^2 - 137/4#

Check by developing:

#v(t) = x^2 + 11t + 121/4 - 137/4 = t^2 + 11t - 4 .# OK