How do you factor #81z^2 + 36z + 4#?

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Answer 1 · 2015-05-20T12:20:55

Problem: Factor #81z^2+36z+4#.

This is an example of the square of the sum formula:

#(a+b)^2=a^2+2ab+b^2#

#a=9z#
#b=2#

#(9z)^2+2(9z)(2)+2^2#

The factorization of #81z^2+36z+4=(9z+2)^2#.