How do you factor #a^3 - ab^2 - 2a^2 + 2b^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer GiĆ³ May 20, 2015 Collect #a^2# between the first and third term and #-b^2# between the second and forth: #a^2(a-2)-b^2(a-2)=# now collect #(a-2)#: #=(a-2)(a^2-b^2)=(a-2)(a-b)(a+b)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2008 views around the world You can reuse this answer Creative Commons License