How do you factor $4 a^{2} - 28 a + 48$ $4a^2-28a+48$ ?

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Answer 1 · 2015-05-22T23:18:36

$4 a^{2} - 28 a + 48 = 4 (a - 3) (a - 4)$ $4a^2-28a+48=4(a-3)(a-4)$

It's a quadratic so:

$Delta=(-28)^2-4*4*48=16$
$sqrt(Delta)=4$

$a_1=(-(-28)-4)/(2*4)=24/8=3$
$a_2=(-(-28)+4)/(2*4)=32/8=4$

How do you factor 4a^2-28a+484a2−28a+484a^2-28a+48?