How do you FOIL #(3w - 7)(2w - 1)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Alan P. May 23, 2015 Using FOIL with #(3w-7)(2w-1)# #{: ("First", 3wxx2w, " = ", 6w^2), ("Outside", 3wxx(-1), " = ", -3w), ("Inside", (-7)xx2w, " = ", -14w), ("Last", (-7)xx(-1), " = ", 7), ("- - - - - -","- - - - - - - - - -","- -","- - - -"), (" "," "," ",6w^2-17w+7) :}# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1394 views around the world You can reuse this answer Creative Commons License