How do you factor #a^2+20a+64#? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. May 25, 2015 In general: #(a+m)(a+n) = a^2 + (m+n)a + (mxxn)# Notice that #20 = 16 + 4# and #64 = 16 xx 4# So #a^2+20a+64 = (a+16)(a+4)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1532 views around the world You can reuse this answer Creative Commons License