How do you solve compound inequalities $8 x > - 32$ $8x > -32$ or $- 6 x \geq 48$ $-6x>=48$ ?

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How do you solve compound inequalities $8 x > - 32$ $8x > -32$ or $- 6 x \geq 48$ $-6x>=48$ ?

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Answer 1 · 2015-05-29T11:36:26

$8 x > - 32 \to x > - 4$ $8x > -32 rarr x > -4$
$- 6 x \geq 48 \to x \leq - 8 remember to reverse the inequality$ $-6x >= 48 rarr x <= -8 " remember to reverse the inequality"$

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How do you solve compound inequalities $8 x > - 32$ $8x > -32$ or $- 6 x \geq 48$ $-6x>=48$ ?

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How do you solve compound inequalities $8 x > - 32$ $8x > -32$ or $- 6 x \geq 48$ $-6x>=48$ ?