How do you factor #xy³ - 49xyz²#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Bill K. May 29, 2015 Both terms have #x# and #y# as common factors, so #xy^3-49xyz^2=xy(y^2-49z^2)#. But #y^2-49z^2# is the difference of two squares. The final answer is: #xy^3-49xyz^2=xy(y-7z)(y+7z)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1437 views around the world You can reuse this answer Creative Commons License