How do you factor #2y^2+7y+6#?

1 Answer
Don't Memorise
May 30, 2015

#2y^2+7y+6#

We can Split the Middle Term of this expression to factorise it
In this technique, if we have to factorise an expression like #ay^2 + by + c#, we need to think of two numbers such that:

#N_1*N_2 = a*c = 2.6 = 12#
and
#N_1 +N_2 = b = 7#
After trying out a few numbers we get #N_1 = 3# and #N_2 =4#
#3*4 = 12#, and #3+4= 7#

#2y^2+7y+6 = 2y^2+4y +3y +6#
# =2y^2+4y +3y +6#
# =2y(y+2) +3(y +2)#
# =color(green)((2y+3)(y+2)#

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