How do you factor and solve #x^2+5x-24=0#?

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Answer 1 · 2015-05-31T12:49:32

Look for a pair of factors of #24# whose difference is #5#.

#24 = 8 xx 3# and #5 = 8 - 3#

So

#x^2+5x-24#

#= x^2+(8-3)x-(8xx3)#

#= (x+8)(x-3)#

So the solutions of #x^2+5x-24 = 0# are #x=-8# and #x=3#