How do you FOIL #(3x+1/3)(2x-1/9)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Tessalsifi · Kevin B. May 31, 2015 #( 3x + 1/3 ) ( 2x - 1/9 ) = # #3x xx 2x + 3x xx -1/9 + 1/3 xx 2x + 1/3 xx -1/9# #= 6x^2 - x/3 + (2x)/3 - 1/27# #= 6x^2 + x/3 - 1/27# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1747 views around the world You can reuse this answer Creative Commons License