Is #x^2 – 14x + 49# a perfect square trinomial and how do you factor it? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Alan P. Jun 3, 2015 Since #49 = (+-7)^2# and #2xx(-7) = -14# #x^2-14x+49# #color(white)("XXXX")##=(x-7)^2# and therefore #color(white)("XXXX")##x^2-14x+49# is a perfect square. Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 9249 views around the world You can reuse this answer Creative Commons License