How do you FOIL # (4-5x)(7x-3)#?

1 Answer
Jun 4, 2015

Given the expression #(4-5x)(7x-3)# we can expand using FOIL as follows:

F = First = #4 xx 7x = 28x#
O = Outside = #4 xx -3 = -12#
I = Inside = #-5x xx 7x = -35x^2#
L = Last = #-5x xx -3 = 15x#

Add them together to get:

#28x-12-35x^2+15x#

Hmmm. That's not in a very helpful order.

How about starting again, this time first rearranging the terms in standard order of descending rank of powers of #x# before applying FOIL...

#(4-5x)(7x-3) = (-5x+4)(7x-3)#

F = First = #-5x xx 7x = -35x^2#
O = Outside = #-5x xx -3 = 15x#
I = Inside = #4 xx 7x = 28x#
L = Last = #4 xx -3# = -12#

Add them together to get:

#-35x^2+15x+28x-12#

#=-35x^2+43x-12#

Notice that by putting each of the binomial factors in descending order of rank first, FOIL puts the expanded terms in descending order of rank too, and thereby conveniently groups the two middle terms so you can add/subtract them.