Question

What is the vertex, axis of symmetry, the maximum or minimum value, and the range of parabola `f(x)=-2(x-2)^2-4`?

Answer 1

The vertex is the point (2, -4)

Axis of symmetry: x = 2

Since a = -2 is negative, the parabola opens downward, there is a max.

max value: -4

Range of parabola: (-4, -infinity)

graph{-2(x - 2)^2 - 4 [-10, 10, -5, 5]}