Question

How do you factor `8x^3 - 27y^3`?

Answer 1

`8x^3 - 27y^3=(2x-3y)(4x^2+6xy+9y^2)`

Explanation:

Use the identity `a^3 - b^3 = (a - b)(a^2 + ab + b^2)`

`a=2x`
`b=3y`

`8x^3 - 27y^3 = (2x - 3y)(4x^2 + 6xy + 9y^2)`