Question

How do find the vertex and axis of symmetry, and intercepts for a quadratic equation `y= -3x^2 + 5`?

Answer 1

`y = -3x^2 + 5`

Explanation:

x of vertex:`x = -b/2a = 0`
y of vertex: y = 5
Axis of symmetry = x of vertex = 0.
y-intercept: y = 5
x-intercepts: y = 0

`3x^2 = 5` --> `x^2 = 5/3`--> `x = +- sqrt5/sqrt3`