Question

A firework is launched from the ground at a velocity of 180 feet per second. Its height after t (t is the variable) seconds is given by the polynomial -16^2 + 180t. How do you find the height of the firework after 2 seconds and after 5 seconds?

Answer 1

In your equation I think there is a `t` missing!!!
I think it should read:
`h=180t-16t^2`

Explanation:

`h` is the height reached starting with an initial velocity of `180 (ft)/s` and considering an acceleration of gravity of `32 (ft)/(s^2)`:
`h(t)=v_it-1/2(32)(t)^2`

`h(t)=180t-16t^2`

for:
`t=2 s`
`h(2)=color(red)(296) ft`
`t=5 s`
`h(5)=color(red)(500) ft`