Question

How do you factor `4-4x^2-4y^2+8xy`?

Answer 1

4, (1+x-y), (1-x+y)

Explanation:

`4−4x^2−4y^2+8xy=4{1^2-(x^2-2xy+y^2)}=4{1^2-(x-y)^2}=4(1+x-y)(1-x+y)`