How do you factor 4-4x^2-4y^2+8xy? Algebra Polynomials and Factoring Factoring Completely 1 Answer Mir Tareq Jun 13, 2015 4, (1+x-y), (1-x+y) Explanation: 4−4x^2−4y^2+8xy=4{1^2-(x^2-2xy+y^2)}=4{1^2-(x-y)^2}=4(1+x-y)(1-x+y) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 2980 views around the world You can reuse this answer Creative Commons License