What is the period and amplitude for #y=2tan(3x-pi2)#?

1 Answer
Jun 19, 2015

Amplitude= #oo#
Period= # (pi^2+pi)/3#

Explanation:

The amplitude is infinity. Because the #tan# function is increasing over its whole domain of definition.
graph{tanx [-10, 10, -5, 5]}

The period of any #tan# is the value of #x# when the "inside" of the #tancolor(red)()# function equals #pi#.

I'll assume that,
#y=2tan(3x-pi^2)#

For a period #3x-pi^2=pi#

#=>x=(pi^2+pi)/3#