How do you factor #54r^3 - 45r^2 + 9r#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nghi N. Jul 2, 2015 Factor: #f(r) = 54r^3 - 45r^2 + 9r# Explanation: #f(r) = 7r(6r^2 - 5r + 1)# Factor the trinomial in parentheses: #(6r^2 - 3r - 2r + 1) = 3r(2r - 1) - (2r + 1) = (2r -1)(3r - 1)# #f(r) = 7r(2r - 1)(3r - 1)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1394 views around the world You can reuse this answer Creative Commons License