How do you the slope & the y - intercept for $f (x) = - 5 x - 9$ $f(x) = -5x - 9$ ?

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Answer 1 · 2015-07-10T23:13:27

The slope is $- 5$ $-5$ , and the $y$ $y$ -intercept is at ( $0, - 9$ $0,-9$ ).

The "slope-intercept" form of a straight line equation is

$y = m x + b$ $y = mx + b$ ,

where $m$ $m$ is the slope and $b$ $b$ is the $y$ $y$ -intercept.

Your equation is

$f (x) = - 5 x - 9$ $f(x) = -5x - 9$

If we compare the two equations, we see that

$m = - 5$ $m = -5$ and $b = - 9$ $b = -9$ .

So the slope is $- 5$ $-5$ and the $y$ $y$ -intercept is at ( $0, - 9$ $0,-9$ ).

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How do you the slope & the y - intercept for f(x)=−5x−9f(x) = -5x - 9 ?