Question

How do graph, find the vertex and axis of symmetry for a quadratic equation `f(x)= -x^2+2x+1`?

Answer 1

`f(x) = - x^2 + 2x + 1`

Explanation:

x-coordinate of vertex: `x = (-b/(2a)) = (-2)/-2 = 1`
y-coordinate of vertex: y = f(1) = - 1 + 2 + 1 = 2

x of axis of symmetry = x of vertex = 1
graph{-x^2 +2x + 1 [-10, 10, -5, 5]}