Question

How do you solve `y < 3x + 2` and `y < -2x + 1`?

Answer 1

Solve system
(1) y < 3x + 2
(2) y < -2x + 1

Explanation:

First graph the Line (1): y = 3x + 2 by its 2 intercepts.
Make x = 0 --> y = 2. Make y = 0 --> x = - 2/3
The solution set of inequality (1) is the area below the Line (1). Shade or color it.
Next, graph Line (2): y = -2x + 1.
Make x = 0 --> y = 1. Make y = 0 --> x = 1/2
The solution set is the area below Line (2). Shade or color it.
The compound solution set is the commonly shared area.