How do you solve $sqrt(3x+1)=5$ ?

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Answer 1 · 2015-07-18T00:03:42

$x=8$

$sqrt(3x+1)=5$

Square both sides.

$3x+1=5^2$

$3x+1=25$

Subtract $1$ from both sides.

$3x=25-1$ =

$3x=24$

Divide both sides by $3$ .

$x=24/3$ =

$x=8$

How do you solve sqrt(3x+1)=5sqrt(3x+1)=5?