How do you solve #y>x+1# and #y<2/3x + 3#?

1 Answer
Jul 18, 2015

Solve the system:
(1) y > x + 1
(2) # y < (2x)/3 + 3#

Explanation:

First graph Line (1): y = x + 1 by its 2 intercepts.
Make x = 0 --> y = 1. Make y = 0 --> x = - 1.
The solution set of the inequality (1) is the area above the Line (1). Color or shade it.

Next, graph the Line (2): #y = (2x)/3 + 3#
Make x = 0 --> y = 3. Make y = 0 --> #x = - 9/2#
The solution set of the inequality (2) is the area below this Line (2). Shade or color it.
The compound solution set of the system is the commonly shared area.