Question

How do you solve `y>x+1` and `y<2/3x + 3`?

Answer 1

Solve the system:
(1) y > x + 1
(2) `y < (2x)/3 + 3`

Explanation:

First graph Line (1): y = x + 1 by its 2 intercepts.
Make x = 0 --> y = 1. Make y = 0 --> x = - 1.
The solution set of the inequality (1) is the area above the Line (1). Color or shade it.

Next, graph the Line (2): `y = (2x)/3 + 3`
Make x = 0 --> y = 3. Make y = 0 --> `x = - 9/2`
The solution set of the inequality (2) is the area below this Line (2). Shade or color it.
The compound solution set of the system is the commonly shared area.