Question

How do you calculate the slope, x intercept, and y intercept of the following equation: `y=2x^3-3x^2-12x`?

Answer 1

I found:
Slope`=6x^2-6x-12`
Y-intercept: `x=0, y=0`
X-intercepts:
`x=0, y=0`
`x=(3+sqrt(105))/4, y=0`
`x=(3-sqrt(105))/4, y=0`

Explanation:

Have a look:

Graphically:
graph{2x^3-3x^2-12x [-65.85, 65.8, -32.9, 32.97]}