How do you solve #2 + 5x < 37#?

1 Answer
Psykolord1989 .
Jul 28, 2015

Subtract 2 from both sides, then divide both sides by 5 to obtain #x<7#

Explanation:

#2 + 5x < 37# (Initial form)

#2 + 5x - 2 < 37 - 2# (Subtract 2 from both sides to isolate #5x# on one side of the inequality)

#5x < 35# (Result of subtraction)

#(5x)/5 < 35/5# (Divide both sides by 5)

(Note: If instead we were dividing by a negative number, then the direction of the inequality would flip. Here we are dividing by a positive, though, so that won't occur)

#x < 7# (Result of division)

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