What is the slope and y-intercept of the line x + y + 2 = 0?

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What is the slope and y-intercept of the line x + y + 2 = 0?

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Answer 1 · 2015-07-30T08:04:21

slope = -1
intercept = -2

Explanation:

The standard equation of the line in the slope-intercept form is $y = m x + c$ $y = mx+c$ , where $m$ $m$ is the slope and $c$ $c$ is the intercept.

So our work is to get the equation in this particular form.

$x + y + 2 = 0$ $x + y + 2 = 0$
$\Rightarrow y = - x - 2$ $=> y = -x - 2$
$\Rightarrow y = (- 1) x + (- 2)$ $=> y = (-1) x + (-2)$
This is an equation in the slope-intercept form, and we can compare it with the equation $y = m x + c$ $y = mx+c$ to get $m = - 1$ $m = -1$ and $c = - 2$ $c = -2$ .

(Try and draw a graph, and it would be very clear to you what the negative slope and intercept means.)

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What is the slope and y-intercept of the line x + y + 2 = 0?

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