How do you solve #sqrtv = 2#?

1 Answer
Stefan V.
Aug 5, 2015

#v = 4#

Explanation:

Take a look at what you have here

#sqrt(v) = 2#

You take the square root from an unknown number #v# and get an integer as the result. This automatically means that the number under the square root is a perfect square.

You can solve for #v# by squaring both sides of the equation.

#(sqrt(v))^2 = 2^2#

#v = color(green)(4)#

This is the only solution to your equation, #x=4#, which is indeed a perfect square.

Related questions
See all questions in Radical Equations
Impact of this question
1759 views around the world
You can reuse this answer
Creative Commons License