How do you solve #sqrt(8 x + 1) = 5#?

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Answer 1 · 2015-08-06T06:19:35

#color(blue)(x=3#

#sqrt(8x+1) = 5#

Squaring both sides

#(sqrt(8x+1))^2 = 5^2#

#8x+1 =25#

#8x = 25-1#

#8x=24#

#color(blue)(x=3#