Question

How do you find the inverse function of: `y = (x+1) / (2x + 1)`?

Answer 1

`x= (1-y)/(2y-1)`

Explanation:

Given `y = (x+1)/(2x+1)`

`color(white)("XXXX")` `2xy+y = x+1`

`color(white)("XXXX")` `2xy-x-1+y = 0`

`color(white)("XXXX")` `x(2y-1) -1+y = 0`

`color(white)("XXXX")` `x(2y-1) = 1-y`

`color(white)("XXXX")` `x = (1-y)/(2y-1)`