Question

How do you foil `(y+7)(y+4)`?

Answer 1

`(y+7)(y+4) = (y^2+11y+28)`

Explanation:

Evaluating the product of two binomials using FOIL:

Sum
`color(white)("XXXX")`product of First terms
`color(white)("XXXX")`product of Outside terms
`color(white)("XXXX")`product of Inside terms
`color(white)("XXXX")`product of Last terms

For the given example: `(y+7)(y+4)`
`color(white)("XXXX")`First terms: `y, y` `color(white)("XXXX")`Product `= y^2`
`color(white)("XXXX")`Outside terms: `y, 4` `color(white)("XXXX")`Product `= 4y`
`color(white)("XXXX")`Inside terms: `7, y` `color(white)("XXXX")`Product `= 7y`
`color(white)("XXXX")`Last terms: 7, 4color(white)("XXXX")#Product `= 28`

Sum
`color(white)("XXXX")` `= y^2+4y+7y+28`

`color(white)("XXXX")` `= y^2+11y+28`