Question

How do you solve `X^2>16`?

Answer 1

`x > 4` or `x < -4`

Explanation:

If `x >=0` and `x^2 > 16`
then `x > sqrt(16) = 4`

If `x > 0` and `x^2 > 16`
then `-x > sqrt(16) = 4`
and (multiplying by `(-1)` which reverses the inequality sign)
`color(white)("XXXX")` `x < -4`