How do you factor $x^{2} - 3 x - 18$ $x^2-3x-18$ ?

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Answer 1 · 2015-08-08T19:30:24

By inspection you need 2 numbers that multiply together to -18 and sum to -3. These numbers are -6 and 3. Therefore we have:

$x^{2} - 3 x - 18 = (x - 6) (x + 3)$ $x^2-3x-18=(x-6)(x+3)$

How do you factor x^2-3x-18x2−3x−18x^2-3x-18?