Question

How do you factor `8x^2+65x+8`?

Answer 1

Factor `y = 8x^2 + 65x + 8`

Ans: (8x + 1)(x + 8)

Explanation:

Use the new AC Method. y = 8(x - p)(x - q).
Converted trinomial`y' = x^2 + 65x + 64 =`(x - p')(x - q').
p' and q' have same sign (a and c same sign)
Factor pairs of 64 -> (1, 64). This sum is 65 = b.
Then p' = 1 and q' = 64.
Therefor,`p = (p')/a = 1/8` and `q = 64/8 = 8`

`y = 8(x + 1/8)(x + 8) = (8x + 1)(x + 8)`