How do you factor #2x^2 + 10x + 12 = 0#?

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Answer 1 · 2015-08-10T15:35:52

#color(blue)((2x+4)(x+3)# is the factorised form for the expression.

#2x^2+10x+12=0#

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like #ax^2 + bx + c#, we need to think of 2 numbers such that:

#N_1*N_2 = a*c =2*12 = 24#

and,

#N_1 +N_2 = b = 10#

After trying out a few numbers we get #N_1 = 6# and #N_2 =4#
#6*4 = 24#, and #6+4=10#

#2x^2+color(blue)(10x)+12= 2x^2+color(blue)(6x +4x)+12#

#=2x(x+3) + 4(x+3)#

#color(blue)((2x+4)(x+3)# is the factorised form for the expression.