Question

How do you solve the inequality: `x^2 - 3x + 5 < 0`?

Answer 1

This inequality has no solutions.

Explanation:

First step to solve such inequality is to calculate the determinant:

`Delta=b^2-4ac=(-3)^2-4*1*5=9-20=-11`

`Delta` is less than zero, and `a` is positive (1), so the whole graph of the function is above X axis.

graph{x^2-3x+5 [-9.96, 10.04, -4.92, 5.08]}

This means the inequality has no solutions.