How do you multiply #(3x + 4)^2#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Don't Memorise Aug 23, 2015 #=color(blue)(9x^2+24x+16# Explanation: #(3x+4)^2 = color(blue)((3x+4)) * (3x+4)# #= color(blue)((3x)) * (3x+4) +color(blue)((4))(3x+4)# #=9x^2+12x+12x+16# #=color(blue)(9x^2+24x+16# Note: The property:#color(blue)((a+b)^2=a^2+2ab+b^2# can be applied to the same expression Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 8691 views around the world You can reuse this answer Creative Commons License