How do you foil #(5x+2)(3x-7)#?

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Answer 1 · 2015-08-26T05:09:01

#=color(blue)(15x^2-29x-14#

The expression is :# (5x +2)(3x-7)#

F O I L involves carrying out the below operations in the following order:

1) product of First terms :#(color(blue)(5x and 3x))#+

2)product of Outside terms:#(color(blue)(5x and -7))#+

3)product of Inside terms:#(color(blue)(2 and 3x))#+

4)product of Last terms:#(color(blue)(2 and -7))#

1) #5x *3x=color(blue)(15x^2) +#

2) #5x * -7=color(blue)(-35x)+#

3) #2 * 3x = color(blue)(6x)+#

4) #2 *-7 = color(blue)(-14#

adding all the terms

#=color(blue)(15x^2-35x+6x-14#
#=color(blue)(15x^2-29x-14#