How do you foil # (6x – 3)(–5x + 2)#?

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Answer 1 · 2015-08-26T12:54:51

#=color(blue)(-30x^2+27x-6#

The expression is :# (6x−3)(-5x +2)#

F O I L involves carrying out the below operations in the following order:

1) product of First terms :#(color(blue)(6x and -5x))#+

2)product of Outside terms:#(color(blue)(6x and 2))#+

3)product of Inside terms:#(color(blue)(-3 and -5x))#+

4)product of Last terms:#(color(blue)(-3 and 2))#

1) #6x *-5x=color(blue)(-30x^2) +#

2) #6x* 2=color(blue)(12x)+#

3) #-3 * -5x = color(blue)(+15x)+#

4) #-3 *2 = color(blue)(-6#

adding all the terms

#=color(blue)(-30x^2+12x+15x-6#
#=color(blue)(-30x^2+27x-6#