How do you foil #(–14x + 11)(–9x + 19)#?

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Answer 1 · 2015-08-27T02:31:57

#=color(blue)(126x^2-365x+209#

The expression is :#(–14x+11)(–9x+19)#

F O I L involves carrying out the below operations in the following order:

1) product of First terms :#(color(blue)(-14x and -9x))#+

2)product of Outside terms:#(color(blue)(-14x and 19))#+

3)product of Inside terms:#(color(blue)(11 and -9x))#+

4)product of Last terms:#(color(blue)(11 and 19))#

1) #-14x *-9x=color(blue)(126x^2) +#

2) #-14x * 19=-color(blue)(266x)+#

3) #11 * -9x = color(blue)(-99x)+#

4) #11 *19 = color(blue)209#

adding all the terms

#=color(blue)(126x^2-266x-99x+209#
#=color(blue)(126x^2-365x+209#