How do you factor completely: $- 4 x^{2} + 16 x - 24$ $−4x^2 + 16x − 24$ ?

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Answer 1 · 2015-08-28T15:19:58

Factor: -4x^2 + 16x - 24

f(x) = -4(x^2 - 4x + 6)
D = b^2 - 4ac = 16 - 24 = -8 < 0
The trinomial in parentheses can't be factored since it doesn't have 2 real roots.

How do you factor completely: −4x2+16x−24−4x^2 + 16x − 24?